I will try to answer the original question.
To a first approximation, the draw weight is directly proportional to the distance of string travel as it is drawn (this is less than the draw length, because of the bracing height and handle thickness. For a "draw length" of 28", the "distance drawn" might be about 20".)
This approximation is usually pretty close if the bow is long compared with the draw length, but goes astray for bows that are very short.
The draw weight is:-
directly proportional to the width of the bow,
proportional to the cube of the thickness,
inversely proportional to the cube of the length.
So, if you keep the width and draw length the same, but reduce both length and thickness by 10%, you will have exactly the same draw weight. If you also reduce the distance drawn by 10%, you will reduce draw weight by 10%. If you want to return to the draw-weight of the original, then increase the width by 10%.