OK - 26" shaft with 2# weight bends x distance. Why a complicated formula to figure out the spine?
If all the shafts in a bunch bend the same distance, the spine should be the same. As long as they pretty close together, who cares! Of course, I have not been a persistent archer over the last 60-65 years, and didn't own a set of matched arrows until I got my first bow(by luck), but I haven't made very many arrows from scratch, either! Maybe I am overthinking this thing. Assuming the same wood of course.
Hawkdancer