Just from what I know of physics, but I'm not sure of what'll happen, so I'd like to know what speeds you get with a 500 grain arrow..
I guess kinetic energy doesn't decrease until arrows are extremely heavy (2000+ grains? Dunno) so calculating with constant KE could be more useful than with constant momentum. It's just because..
speed * mass = momentum
(1/2) * speed * speed * mass = kinetic energy
I have no idea why this is the case or what they really represent, other than some stuff about work being force times distance (the force of the bow's pull and the distance of the draw length) and sort of corresponding to kinetic energy as potential energy...
(1/2) * 185fps * 185fps * 375grain = 6417187.5 fps^2 grains = 38.6 Joules according to Wolfram Alpha...
So now, it's just Algebra. We take a 500 grain arrow. The speed s is unknown, what we want to find. Realistically, KE would increase some amount with the heavier arrow but in this calculation I assume it's the same (6417187.5), so this would be a minimum expected arrow speed; it'd probably be more.
(1/2) * s * s * 500grain = 6417187.5 fps^2 grains
*2 both sides
s * s * 500grain = 12834375 fps^2 grains
/500grains both sides
s * s = 25668.75 fps^2
square root both sides
s = 160.21fps
Assuming the KE was constant, the momentum would now be
500grains * 160.21fps = 80105.00grains*fps = 1.58 Newton*seconds
Before, it was
375grains * 185fps = 69375grains*fps = 1.37 Newton*seconds. 86.71% as much momentum.
I wish physics was still this fun in university :\ But I just sort of guessed that.. KE would increase more slowly than momentum as arrow weight increases. It makes sense but now I don't even know exactly why.