It's the length of the arrow, not the draw. If you have a bow that draws 45@24".. But you're shooting a 32" arrow, you're going to exert the same inertia forces as someone shooting a 45@30" bow. Although the flex point would be different because the shorter bow would have the paradox at 24", The energy has to travel through the same length of shaft.
I hope I'm explaining it right.
Here's an exaggerated experiment you can do that proves this point. Imagine your hands as the sources of force. One hand is the string exerting forward inertia forces; and the other hand is the point, exerting rearward inertia forces. You can consider your "draw weight" as your maximum arm/chest/back strength used to squeeze your hands together as hard as you can, regardless of what that number might be.
Now take a 3/8 dowel that's 48" long. Put it between your hands like this |=======| Get it bending a little and squeeze your hands together until it snaps (there will be a lot of flex and it wont take much effort). Then take a 3/8 dowel that's 26" long and perform the same experiment. It will take much more force to get it bending and will be difficult to break. If you wanna go real extreme, do the same experiment with a 3/8 dowel that's 10" long. You won't be able to get it to flex and it will be extremely difficult to break with only forward and rearward force.
Your arms, chest, and back strength stayed the same throughout the experiment, but the dowels became increasingly difficult to bend and break.
In physics, the term used is torque. This is force applied multiplied by distance.
So, using a nice round number, say 100# is your maximum squeezing power...
48" x 100# = you are exerting 4,800 units of force on that shaft
26" x 100# = 2,600 units of force
10" x 100# = 1,000 units of force
All controls stayed the same. The "draw weight" stayed the same. The diameter of the shaft stayed the same. The only variable was the shaft length.